WebbSolutions for The values of two resistors are R1 = (6 ± 0.3)k Ωand R2 = (10 ± 0.2)k Ω. The percentage error in the equivalent resistance when they are connected in parallel isa)5.125%b)2%c)3.125%d)7%e)10.125%Correct answer is option 'E'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Webb9 okt. 2024 · Example 1: By ignoring the negative sign, the difference is 2, which is the error. Step 2: Divide the error by actual value; 2/470 = 0.0042531. Multiply this

The values of two resistors are R1 = (6 0.3)k and R2 = (10 0.2)k

WebbKnow about percent error definition, formula, steps of calculation, mean and solved examples online. Find out percent error and mean percent error of the given models. orange coats

The values of two resistors are R1 = (6 ±0.3)kΩ and R2 = (10 ± 0.2)kΩ

Webb16 okt. 2024 · R1= 8.0Ω . dR1 = +- 0.3Ω In series: Net Resistance = R= 20 Ω. % error: 0.5×100/ 20 = 2.5% In parallel: 1/R = 1/R1 + 1/R2 - dR/R^2 = - dR1/R1^2 - dR2/R2^2. R = 8×12/(8+12)= 4.8Ω. dR/R = 4.8 * 0.2/12^2 + 4.8 * 0.3/8^2 = 2.9% :-)) Advertisement Advertisement New questions in Physics. WebbIn order to do this note that the following two statements are equivalent: 1. The true value has a 68% chance of lying within ± sm of the mean value. 2. The mean value has a 68% chance of lying within ± sm of the true value. If the true value actually is 100 units, then there is an approximately 68% chance that the mean will lie between 89 ... Webb25 maj 2024 · Now, % Error in R₁ = ΔR₁/R₁ × 100 = 0.3/6 × 100 = 5 % Value of the Resistor R₂ = (10 +/- 0.2) Ω R₂ = 10 ∴ ΔR₂ = +/- 0.2 Ω ∴ % Error in R₂ = ΔR₂/R₂ × 100 = 0.2/10 × 100 = 2 % A/c to the Question, Resistors are connected in Parallel, ∴ Error % in eq. Resistance (R) = Error % in R₁ + Error % in R₂ ∴ Error % in Eq.Resistance = 5% + 2 % = 7 % orange cocktail napkins