WebSep 8, 2024 · GIVEN: ∠ACB = 50°. As it is rhombus ; diagonals will bisect at 90°. ⇒ Therefore, let the center be O. ∠AOD= ∠AOB= ∠BOC= ∠COD= 90°. Now, In Δ BOC. ⇒ ∠OCB … WebApr 26, 2024 · The diagonals in a rhombus are perpendicular, So, ∠BPC = 90° From triangle BPC, The sum of angles is 180° So, ∠CBP = 180° – 40° – 90° = 50° Since, triangle ABC is isosceles . We have, AB = BC . So, ∠ACB = ∠CAB = 40° Again from triangle APB, ∠PBA = 180° – 40° – 90° = 50° Again, triangle ADB is isosceles, So,
In a Rhombus Abcd, If ∠Acb = 40°, Then ∠Adb
Web(1)如图①,在菱形abcd中,∠a=60°,ab= 6,则菱形abcd的面积为_____ 问题解决: (2)如图2是一块矩形铁片ABCD,其中AB=60厘米,BC=90厘米,李师傅想从这块铁片中裁出一个筝形EFGH,要求点E是AB边的中点,点F、G、H分别在BC、CD、AD上(含端点),是否存在一种 … WebApr 15, 2024 · 6.1 INTRODUCTION In our earlier classes, we have studied various plane figures such as triangles, quadrilaterals, squares, rhombus, rectangles etc. Here we greencross chatswood
ABCD is a rhombus such that $\angle ACB = 50^\circ - Vedantu
WebDec 13, 2024 · Answer: x = 4 Step-by-step explanation: If a quadrilateral is a rhombus, then the diagonals of it will bisect each angle of the quadrilateral. Now, the diagonal AC bisects angle C into ∠ ACD and ∠ ACB. Hence, ∠ ACD = ∠ ACB ⇒ 2x + 4 = 5x - 8 {Given that ∠ ACD= 2x + 4 and ∠ ACB= 5x - 8 } ⇒ 3x = 12 ⇒ x = 4 (Answer) WebFree solutions for R D Sharma Solutions - Mathematics - Class 8 Chapter 18 - Understanding Shapes Special Types Quadrilaterals Understanding Shapes Special Types Quadrilaterals Exercise 17.2 question 5. These explanations are written by Lido teacher so that you easily understand even the most difficult concepts Webb) the size of c) the value b length of AC Solution a) b) c) 0 0 ˆ ˆ A=50 , C=32 and AB=5cm ˆ B 0 0 sin sin 5 sin50 sin32 7,23 a c A C a a = = = [] 0 ˆ 98 B sumof sina = Ð D 0 0 sin sin 5 sin98 sin32 9,34 b c B C b b = = = B a b 5 c cm = C 32 Then we know now all the angles and lengths of the sides in this triangle. green cross certification